Curse

SlitUrNek · Apr 13, 2006, 08:10 PM // 20:10

It may just be that i have been writing c++ all day but i am stuck on this

it will be a very small program that will print

+_____+
_+___+
__+_+
___+

the catch, it must be done by for loops not a ton of cout's
toss me some code if any of you can, ty in advance

dont mind the "_" it was just a way for you to see the design, count the _ as spaces

Eclair · Apr 13, 2006, 08:38 PM // 20:38

if you still need it:

something like uh

char[7] print = (' ', ' ', ' ', ' ', ' ', ' ', ' ') //err, basically just create an array of chars and initialize it all to the space character.

for (int i = 0; i < 4; i++)
{
char[i] = '+';
char[7-i] = '+';
cout << char << endl; //this should print out the entire array of chars, if it doesn't uh, just make another for loop that iterates through each element and print that.
char[i] = '_';
char[7-i] = '_';
}

That should work, not sure if it fits all the criteria though.

SlitUrNek · Apr 13, 2006, 09:15 PM // 21:15

i dont entirly understand the char[] i havent gotten that far yet here take a look at my other 2 patters if u can get a grasp
i was thinking of using setw(), but will setw hold a variable and not numeric and i would just through the setw through a loop for my spaces +/-

#include
#include //for setw
using namespace std;

int main ()
{
int col, row;
char mychar = '+';

//Pattern 1
for (col=1; col <= 5; ++col)
{
cout << endl;
for (row=0; row < col; ++row)
{
cout << mychar;
}
}

//Pattern 1 part 2
for (col=0; col <= 5; ++col)
{
cout << endl;
for (row=4; row >= col; --row)
{
cout << mychar;
}
}

//Pattern 2
cout << endl;
for (col=0; col < 5; ++col)
{
cout << endl;
for (row=0; row < 4 - col; ++row)
{
cout << " ";
}
for (row=0; row < 2 * col + 1; ++row)
{
cout << mychar;
}
}

//Pattern 3
cout << endl;

return 0;
}

Eclair · Apr 13, 2006, 09:56 PM // 21:56

err, well, a char[] is an array of chars.

Think of it this way char[7] means that you have an array of 7 slots, and their names are 0-7, so for example:

0 1 2 3 4 5 6 7

now: char[0] = 'a';

0 1 2 3 4 5 6 7
a

char[6] = 'b';

0 1 2 3 4 5 6 7
a b

you access them the same way.

char temp = char[0];

now temp will contain whatever is stored in char[0] which in this case is 'a'.

Now, if you're not allowed to use arrays, its going to be annoying. You'll probably have to do some for loops within for loops

SlitUrNek · Apr 13, 2006, 10:05 PM // 22:05

well, this chapter is using for loops in c++ so i would asume that is what i am to do, i dont see why i cant cheat it a bit and use char[] eh?

if i am going to use char[] how do i declare each
exampl: char[7] = (' '; ' '; ' '; ' '; ' '; ' '; ' ')
so char will set each slot 0-6 will spaces?
or must i go through and declaire each one?

Eclair · Apr 13, 2006, 10:53 PM // 22:53

whoops, had a typo, if uh, you're using a char array, do

char[7] print;

for (int i = 0; i < 7; i++)
print[i] = ' ';

SlitUrNek · Apr 13, 2006, 11:07 PM // 23:07

actualy i have figured it out with some help from a friend, if ur interested in what it was soposed to look like, here you go

for (col=0; col < 5; ++col)
{
cout << endl;
for (row=0; row < col; ++row)
{
cout << " ";
}

for (row =col; row <= col; ++row)
{
cout << "+";
}

for (row=0; row < 5 - col*2 ; ++row)
{
cout << " ";
}

for (row=col; row <4 ;row++ )
{
cout << "+";
break;
}
}

benmanhaha · Apr 14, 2006, 10:16 PM // 22:16

I would have done it this way, but I don't know if it would meet the requirements.
And make sure to remove any "_" symbols and replace them with spaces.

#include
#include
using namespace std;

int main()
{
int i;
for(i = 1; i != 0; i--)
{
cout << "+_____+" << endl;
Sleep(1000);
system("cls");
cout << " +___+ " << endl;
Sleep(1000);
system("cls");
cout << " +_+ " << endl;
Sleep(1000);
system("cls");
cout << " + " << endl;
Sleep(2000);
system("cls");
}
return 0;
system("pause");//Only for Dev C++ Compiler
}